The smallest among √1/2, √1/3, √1/4, and √3/2 is || ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS
The smallest among √1/2
, √1/3
, √1/4
, and √3/2
is:
(A) √3/2
(B) √1/2
(C) √1/3(D) √1/4
Solution:
To determine the smallest value among √1/2
, √1/3
, √1/4
, and √3/2
, we can compare these values by evaluating their numerical values:
√1/2 = √0.5
√1/3 = √(1/3)
√1/4 = √0.25
√3/2 = √1.5
Now, we find the decimal values of these square roots:
√0.5 ≈ 0.7071
√(1/3) ≈ 0.5774
√0.25 = 0.5
√1.5 ≈ 1.2247
Comparing these values, we see:
√0.5 ≈ 0.7071
√(1/3) ≈ 0.5774
√0.25 = 0.5
√1.5 ≈ 1.2247
Among these, the smallest value is √0.25
.
Therefore, the smallest value is √1/4
, which corresponds to option (D).
Why this quesiton is important?
- Fundamental Concept: Helps understand and compare square roots and their numerical values.
- Previous Exam Question: Was asked in ADRE's SLRC-2022 Paper III for Grade-III post, indicating its relevance in competitive exams.
- Improves Calculation Skills: Enhances ability to perform approximate calculations and comparisons.
- Common in Various Exams: Similar questions frequently appear in other competitive exams, making it a valuable practice problem.
😀👍
ReplyDelete