The smallest among √1/2, √1/3, √1/4, and √3/2 is || ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS

The smallest among √1/2, √1/3, √1/4, and √3/2 is:

(A) √3/2

(B) √1/2

(C) √1/3

(D) √1/4


Solution:

To determine the smallest value among √1/2, √1/3, √1/4, and √3/2, we can compare these values by evaluating their numerical values:

  • √1/2 = √0.5
  • √1/3 = √(1/3)
  • √1/4 = √0.25
  • √3/2 = √1.5

Now, we find the decimal values of these square roots:

  • √0.5 ≈ 0.7071
  • √(1/3) ≈ 0.5774
  • √0.25 = 0.5
  • √1.5 ≈ 1.2247

Comparing these values, we see:

  • √0.5 ≈ 0.7071
  • √(1/3) ≈ 0.5774
  • √0.25 = 0.5
  • √1.5 ≈ 1.2247

Among these, the smallest value is √0.25.

Therefore, the smallest value is √1/4, which corresponds to option (D).



Why this quesiton is important?


  • Fundamental Concept: Helps understand and compare square roots and their numerical values.
  • Previous Exam Question: Was asked in ADRE's SLRC-2022 Paper III for Grade-III post, indicating its relevance in competitive exams.
  • Improves Calculation Skills: Enhances ability to perform approximate calculations and comparisons.
  • Common in Various Exams: Similar questions frequently appear in other competitive exams, making it a valuable practice problem.

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