The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is || ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS
The number when divided by 2, leaves remainder 1; when divided by 3, leaves remainder 2 and when divided by 4, leaves remainder 3, is:
(A) 25
(B) 41
(C) 13
(D) 11
Solution:
Let's find the number htat satisfies the conditions:
- x ≡ 1 (mod 2)
- x ≡ 2 (mod 3)
- x ≡ 3 (mod 4)
We start by finding a number x that satisfies x ≡ 1 (mod 2). This means x is odd.
Next, since ≡ 2 (mod 3), x when divided by 3 lives a reainder of 2.
Similarly, x ≡ 3 (mod 4) means when x is divided by 4, the memainder is 3.
To find such a number, we check the options:
- Option A: 25 (odd, check divisibility)
- 25÷2 = 12 remainder 1 (satisfies condition 1)
- 25÷3= 8 remainder 1 (does not satisfy condition 2)
- 25÷4= 6 remainder 1 (does not satisfy condition 3)
Please give me the answer
ReplyDeleteOption D
DeleteThe number x that satisfies all the conditions is 11.
Delete