Find the value of √(225/729) - √(25/144) - √(16/ 81) || ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS
Find the value of √(225/729) - √(25/144) - √(16/ 81)
(A) - 5/9
(B) - 7/12
(C) - 20/27
(D) - 11/ 36
Solution:
To find the value of √(225/729) - √(25/144) - √(16/ 81), we first calculate each square root separately.
√(225/729)
= √225/√729
= 15/27
= 5/9
√(25/144)
= √25/√144
= 5/12
√(16/81)
= √16/√81
= 4/9
Now, we substitute these values back into the expression
5/9 - 5/12- 4/9
= (20-15-16)/36
= -11/36
Therefore, the value is: (D) - 11/ 36
Importance of this question:
- Helps in understanding square roots and fractions.
- evelops skills in simplifying complex expressions.
- A typical type of problem in many mathematics assessments.
- Enhances overall problem-solving abilities.
- Previously asked in ADRE exams, highlighting its importance for exam preparation.
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