Find the value of √(225/729) - √(25/144) - √(16/ 81) || ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS

Find the value of  √(225/729) - √(25/144) - √(16/ 81)

(A) - 5/9

(B) - 7/12

(C) - 20/27

(D) - 11/ 36



Solution: 

To find the value of √(225/729) - √(25/144) - √(16/ 81), we first calculate each square root separately. 


√(225/729)

= √225/√729

= 15/27

= 5/9


√(25/144)

= √25/√144

= 5/12


√(16/81)

= √16/√81

= 4/9


Now, we substitute these values back into the expression

5/9 - 5/12- 4/9

= (20-15-16)/36

= -11/36


Therefore, the value is: (D) - 11/ 36



Importance of this question:

  • Helps in understanding square roots and fractions.
  • evelops skills in simplifying complex expressions.
  • A typical type of problem in many mathematics assessments.
  • Enhances overall problem-solving abilities.
  • Previously asked in ADRE exams, highlighting its importance for exam preparation.




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