A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is: || ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS

Question

A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is: 

    (A) 60 years 

    (B) 51 years 

    (C) 48 years 

    (D) 45 years

ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS


Solution: 

To determine the present age of the man's wife, follow these steps:

  1. Determine the son’s present age:

    • The son will be 15 years old in 3 years.
    • Therefore, the son’s current age is 153=1215 - 3 = 12 years.
  2. Calculate the man’s present age:

    • The man is four times as old as his son.
    • Thus, the man’s current age is 4×12=484 \times 12 = 48years.
  3. Find the wife’s present age:

    • The man is 3 years older than his wife.
    • Therefore, the wife’s current age is 483=4548 - 3 = 45 years.

The correct answer is (D) 45 years.


Importance for ADRE 2.0:

  1. Arithmetic Problem-Solving: Tests skills in solving age-related problems using basic arithmetic operations, which are common in competitive exams.
  2. Logical Reasoning: Assesses the ability to apply logical reasoning to deduce the present age based on given future conditions.
  3. Exam Preparation: Provides practice for similar age-related questions that may appear in ADRE 2.0, enhancing problem-solving abilities.

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