A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is: || ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS
Question
A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, the present age of his wife is:
(A) 60 years
(B) 51 years
(C) 48 years
(D) 45 years
![]() |
ADRE 1.0 SLRC 2022 PAPER-III SOLVED QUESTIONS |
Solution:
To determine the present age of the man's wife, follow these steps:
Determine the son’s present age:
- The son will be 15 years old in 3 years.
- Therefore, the son’s current age is years.
Calculate the man’s present age:
- The man is four times as old as his son.
- Thus, the man’s current age is years.
Find the wife’s present age:
- The man is 3 years older than his wife.
- Therefore, the wife’s current age is years.
The correct answer is (D) 45 years.
Importance for ADRE 2.0:
- Arithmetic Problem-Solving: Tests skills in solving age-related problems using basic arithmetic operations, which are common in competitive exams.
- Logical Reasoning: Assesses the ability to apply logical reasoning to deduce the present age based on given future conditions.
- Exam Preparation: Provides practice for similar age-related questions that may appear in ADRE 2.0, enhancing problem-solving abilities.
Comments
Post a Comment